PHP | mysqli_connect() Function

Hello folks! welcome back to a new edition of our tutorial on PHP. In this tutorial guide, we are going to be studying about the PHP mysqli_connect() Function.

The mysqli_connect() function establishes a connection with MYSQL server and returns the connection as an object.

Syntax

Following below is the syntax to use this function -

mysqli_connect([$host, $username, $passwd, $dname, $port, $socket] )

READ: PHP | mysqli_autocommit() Function

Parameter Details

Sr.No	Parameter & Description
1	host(Optional) This represents a host name or an IP address. If you pass Null or localhost as a value to this parameter, the local host is considered as host.
2	username(Optional) This represents a user name in MySQL.
3	passwd(Optional) This is represents the password to the given user.
4	dname(Optional) This represents the default database in which the queries should be performed.
5	port(Optional) This represents the port number at which you want to establish a connection to MySQL Server.
6	socket(Optional) This represents the socket that is to be used.

Return Value

This built-in function returns the connection object, if a connection got established to a MYSQL server successfully. In case of an unsuccessful connection, this built-in PHP function returns the boolean value false.

PHP Version

This built-in function was first introduced in PHP version 5 and it works in all of the later versions.

Example1

The following example below illustrates the usage of PHP mysqli_connect() function (in a procedural style) -

<?php
   $host = "localhost";
   $username  = "root";
   $passwd = "password";
   $dbname = "mydb";

   //Creating a connection
   $con = mysqli_connect($host, $username, $passwd, $dbname);

   if($con){
      print("Connection Established Successfully");
   }else{
      print("Connection Failed ");
   }
?>

Output

When the above code is executed, it will produce the following result -

Connection Established Successfully

Example2

In an object oriented style you can use new mysqli() construct in creating a connection as follows $minus;

<?php
   $host = "localhost";
   $username  = "root";
   $passwd = "password";
   $dbname = "mydb";

   //Creating a connection
   $con = new mysqli($host, $username, $passwd, $dbname);

   if($con->connect_errno){
      print("Connection Failed ");
   }else{
      print("Connection Established Successfully");
   }

   //Closing the connection
   $con -> close();
?>

Output

When the above code is executed, it will produce the following result -

Connection Established Successfully

Example3

You can also invoke this function without passing any parameters as shown below -

<?php
   //Creating a connection
   $con = @mysqli_connect();

   if($con){
      print("Connection Established Successfully");
   }else{
      print("Connection Failed ");
   }
?>

Output

When the above code is executed, it will produce the following result -

Connection Failed

Example4

Try the following example below -

<?php
   $connection_mysql = @mysqli_connect("localhost", "root", "wrong_password", "mydb");
   
   if (mysqli_connect_errno($connection_mysql)){
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
	  exit();
   }   
   echo ("Connection established successfully");    
   mysqli_close($connection_mysql);
?>

Output

When the above code is executed, it will produce the following result -

Failed to connect to MySQL: Access denied for user 'root'@'localhost' (using password: YES)

READ: PHP | mysqli_commit() Function

Alright guys! This is where we are rounding up for this tutorial post. In our next tutorial, we are going to be studying about the PHP mysqli_connect_errno() Function.

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