PHP | mysqli_connect_error() Function

Hello folks! welcome back to a new edition of our tutorial on PHP. In this tutorial guide, we are going to be studying about the PHP mysqli_connect_error() Function.

During the attempt to connect to MYSQL server, if any error occurs the built-in PHP mysqli_connect_error() function returns the description of the error occurred (during the last connection call).

Syntax

Following below is the syntax to use this function -

mysqli_connect_error()

READ: PHP | mysqli_connect() Function

Parameter Details

This built-in function does not accept any parameters.

Return Value

This built-in PHP function returns a string value representing the description of the error from the last connection call, Incase of a failure. If the last connection call was successful, this function returns NULL.

PHP Version

This built-in function was first introduced in PHP version 5 and it works in all of the later versions.

Example1

The following example below demonstrates the usage of built-in mysqli_connect_error() function (in a procedural style) -

<?php
   //Creating a connection
   $con = @mysqli_connect("localhost", "root", "wrong_password", "mydb");

   //Connection Error
   $error = mysqli_connect_error($con);
   print("Error: ".$error);
?>

Output

When the above code is executed, it will produce the following result -

Error: Access denied for user 'root'@'localhost' (using password: YES)

Example2

In an object oriented style the syntax of this function is $con->connect_error(). Following is the example of this function in an object oriented style $minus;

<?php
   //Creating a connection
   $con = @new mysqli("localhost", "root", "wrong_password", "mydb");

   //Connection Error
   $error = $con->connect_error;
   print("Error: ".$error);
?>

Output

When the above code is executed, it will produce the following result -

Error: Access denied for user 'root'@'localhost' (using password: YES)

Example3

The following example demonstrates the behaviour of PHP mysqli_connect_error() function Incase of a successful connection -

<?php
   //Creating a connection
   $con = @mysqli_connect("localhost", "root", "password", "mydb");
   
   //Connection Error
   $error = mysqli_connect_error();
   if(!$con){
      print("Connection Failed: ".$error);
   }else{
      print("Connection Established Successfully");
   }
?>

Output

When the above code is executed, it will produce the following result -

Connection established successfully

Example4

Try the following example below -

<?php
   $connection = @mysqli_connect("localhost","root","wrong_pass","wrong_db");
   
   if (!$connection){
      die("Connection error: " . mysqli_connect_error());
   }
?>

Output

When the above code is executed, it will produce the following result -

Connection error: Access denied for user 'root'@'localhost' (using password: YES)

READ: PHP | mysqli_connect_errno() Function

Alright guys! This is where we are going to be rounding up for this tutorial post. In our next tutorial, we are going to be discussing about the PHP mysqli_debug() Function.

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